Practice Quiz 14
Choose the best answer
- Which of the following is true about
gravitational force between two objects.
- It is inversely proportional to the cube of the
distance separating them
- It is proportional to the square of the distance
separating them.
- It is inversely proportional to the square of
the distance separating them.
- It is proportional to the distance separating them.
- It is inversely proportional to the distance
separating them.
Answer: C
- If the distance between two objects is multiplied
by a factor of 10
, then the gravitational force
between the objects is multiplied by a
factor of
- 0.1
- 10
- 1
- 0.01
- 100
Answer: D
- Object 1 and Object 2 are located on the x-axis at
x = 1500 m and x = 600 m respectively. What is the
direction of the gravitational force exerted by
object 1 on object 2?
- South
- It can not be determined
- North
- West
- East
Answer: E
- Calculate the distance between an object of mass
2000 kg and an object of mass 6000 kg,
if they are exerting a gravitational force of 9e-9 N
on each other.
- 468.978 m
- 71.061 m
- 298.217 m
- 203.014 m
- 329.9 m
Answer: C
- A satelite of mass 600000 kg is revolving around
earth at an altitude of 5000 km above the surface of
earth. Earth has a mass of 5.98e24 kg and a radius of 6.38e6 m.
Calculate the acceleration with which the satelite is revolving
around earth.
- 4.181 m ⁄ s 2
- 4.531 m ⁄ s 2
- 3.08 m ⁄ s 2
- 1.719 m ⁄ s 2
- 3.841 m ⁄ s 2
Answer: C
- A car of mass 2400 kg is turning on a curve
. The coeffient of friction between the tires of the
car and the ground is 0.2. It is found that the
maximum speed by which the car can make it
on the curve without sliding is 25 m ⁄ s. Calculate
the radius of curvature of the curve.
- 410.114 m
- 474.506 m
- 153.728 m
- 247.334 m
- 318.878 m
Answer: E
- An object of mass 0.3 kg is revolving in a
circular path of radius 0.1 m on a friction less
table by means of a string which is attached to
a hanging object of mass 4.5 kg (the string is attached
to the hanging object through a hole on the table
at the center of the circular path). Calculate
the speed with which the object on the table
is revolving on the circular path.
- 3.834 m ⁄ s
- 2.995 m ⁄ s
- 0.692 m ⁄ s
- 2.306 m ⁄ s
- 1.889 m ⁄ s
Answer: A
- A 0.2 kg pendulum of length 2 m that makes an angle
of 40 deg with the vertical is revolving in
a horizontal circle. Calculate the speed with which
it is revolving on the horizontal circle.
- 2.357 m ⁄ s
- 0.332 m ⁄ s
- 3.251 m ⁄ s
- 3.959 m ⁄ s
- 5.635 m ⁄ s
Answer: C
- An object of mass 2.5 kg is revolving in a vertical
circle of radius 0.5 m. Calculate the minimum
speed at the top of the circle by which the
object can make it without the string slacking.
- 2.214 m ⁄ s
- 3.504 m ⁄ s
- 3.793 m ⁄ s
- 3.053 m ⁄ s
- 1.109 m ⁄ s
Answer: A
- An object of mass 2 kg is revolving in a vertical
circle of radius 0.7 m. If its speed at
the top of the circle is the minimum speed by which
it can make it without the string slacking,
calculate its speed at the bottom of the circle.
- 6.88 m ⁄ s
- 4.3 m ⁄ s
- 5.857 m ⁄ s
- 10.153 m ⁄ s
- 3.481 m ⁄ s
Answer: C