Practice Quiz 10
Choose the best answer
- An object of mass 28.333 kg is located at the top
of a 10 m tall building. Calculate the
gravitational potential energy of the object
with respect to a point 3 m below the top
of the building .
- 1166.459 J
- 832.99 J
- 479.56 J
- 1259.991 J
- 616.244 J
Answer: B
- A bullet of mass 0.0555 kg is fired from a
15 m tall building horizontally with a speed
of 900 m ⁄ s. Calculate its mechanical energy
just after it is fired.
- 22485.659 J
- 42061.888 J
- 6988.274 J
- 27353.34 J
- 17275.824 J
Answer: A
- An object of mass 9 kg is sliding down a friction less
inclined plane of length 2 m that makes an angle
of 70 deg with the horizontal. Calculate the
work done by gravitational force as the object
slides from the top of the inclined plane to the
ground.
- 165.762 J
- 314.714 J
- 204.271 J
- 58.651 J
- 25.681 J
Answer: A
- An object of mass 8 kg is sliding down
a friction less inclined plane of length
10 m that makes an angle of
30 deg. Calculate its speed just before it hits the ground.
- 3.122 m ⁄ s
- 7.228 m ⁄ s
- 12.655 m ⁄ s
- 1.08 m ⁄ s
- 9.899 m ⁄ s
Answer: E
- A roller coaster extends to the ground
from a height of 31 m (point A) and then rises
to a height of 10 m (point B). An object of mass 4 kg
starts at point A with a speed of 5 m ⁄ s. Assuming
the roller coaster is friction less, calculate the
speed of the object by the time it reaches point B.
- 14.418 m ⁄ s
- 20.895 m ⁄ s
- 23.684 m ⁄ s
- 12.484 m ⁄ s
- 4.462 m ⁄ s
Answer: B
- A certain spring extends by 0.3 m when an object
of mass 0.4 kg hangs from it. Calculate
the Hook's constant of the spring.
- 10.938 N ⁄ m
- 13.067 N ⁄ m
- 9.326 N ⁄ m
- 15.35 N ⁄ m
- 22.919 N ⁄ m
Answer: B
- Calculate the elastic potential stored by a
spring of Hook's constant 250 N ⁄ m when it is
compressed by .1 m.
- 0 J
- 2.307 J
- 1.25 J
- 1.107 J
- 1.452 J
Answer: C
- An object of mass 0.75 kg is brought in contact
with a spring of Hook's constant 300 N ⁄ m that is
compressed by 0.175 m. If the spring is let go free to expand,
calculate the speed by which the object will
leave the spring at its relaxed position.
- 2.902 m ⁄ s
- 2.468 m ⁄ s
- 6.153 m ⁄ s
- 1.619 m ⁄ s
- 3.5 m ⁄ s
Answer: E
- Which of the following is not a correct statement.
- Work done by non-conservative forces is equal to
the change in the mechanical energy of the object.
- If all the forces acting on an object are non-
conservative, the mechanical energy is conserved
- Work done by conservative forces is equal to the
the negative of the change in the potential energy of the object
- The force due to a spring is proportional and
opposite to the displacement (compression or
extension) of the spring
- Net work done on an object is equal to the
change in the kinetic energy of the object.
Answer: B
- Intially an object has a potential energy of 10 J
and a kinetic energy of 170 J. Under the influence
of conservative and non-conservative forces
its potential energy changed to 15 J and its kinetic
energy changed to 22 J. Calculate the work done
by the non-conservative forces.
- -150 J
- -137 J
- -143 J
- -135 J
- -148 J
Answer: C
- An object of mass 0.01 kg released from
a height of 13 m has a speed of 3 m ⁄ s just before it
hits the ground. Calculate the work done by air resistance.
- -1.08 J
- -0.728 J
- 0 J
- 0 J
- -1.229 J
Answer: E